25x^2-40x+21=5

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Solution for 25x^2-40x+21=5 equation: 



25x^2-40x+21=5

We move all terms to the left:

25x^2-40x+21-(5)=0

We add all the numbers together, and all the variables

25x^2-40x+16=0

a = 25; b = -40; c = +16;
Δ = b2-4ac
Δ = -402-4·25·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{40}{50}=4/5$

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